ChessProblems.ca Bulletin 7, December 2015.pdf

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CHESSPROBLEMS.CA
Contents
Page
1 Originals
189
2015 Informal Tourney . . . . . . . 189
Hors Concours . . . . . . . . . . . . 192
2 Articles
Michael A. Hudson:
Storming
Fortresses . . . . . . . . . . .
Vlaicu Cri¸an & Eric Huber:
s
Wenigsteiner
in
Proca
Retractor AntiCirce . . . . . .
Adrian Storisteanu: In Messigny . .
Fran¸ois
c
Labelle:
Ataques
Igualitarios: Computer Records
Arno T¨ngler: Series Target Square
u
Tasks . . . . . . . . . . . . . .
Adrian Storisteanu: October blues .
3 Recently
Honoured
Compositions
194
194
.
ISSUE 7 (DECEMBER 2015)
199
202
204
214
235
Canadian
236
4 Last Page
242
Canadian Chess Championship
1906, Montr´al . . . . . . . . 242
e
Editor:
Cornel Pacurar
Collaborators:
Elke Rehder,
.
Adrian Storisteanu, Arno T¨ngler
u
Originals:
originals@chessproblems.ca
Articles:
articles@chessproblems.ca
Correspondence:
bulletin@chessproblems.ca
Pawns Battle
[Painting in Mixed Media on paper,
c
Elke Rehder, http://www.elke-rehder.de. Reproduced with permission.]
.....
ISSN 2292-8324
ChessProblems.ca
Bulletin
IIssue
7I
ORIGINALS
ChessProblems.ca’s annual Informal Tourney
is open for series-movers of any type and
with any fairy conditions and pieces.
Hors
concours
compositions (any genre) are also
welcome!
Send to: originals@chessproblems.ca.
2015 Informal Tourney
T259
Alberto Armeni
T260
Gy¨rgy Bakcsi
o
T261
Paul R˘ican
a
T262
S´bastien Luce
e
2015 Judge:
George P. Sphicas
2015 Tourney Participants:
1. Alberto Armeni
2. Gy¨rgy Bakcsi
o
3. Harald Grubert
4. Michael Grushko
5. L’uboˇ Kekely
s
6. Branko Koludrovi´
c
7. V´clav Kotˇˇovec
a
es
8. Karol Mlynka
9. S´bastien Luce
e
10. Ladislav Packa
11. Cornel Pacurar
12. Paul R˘ican
a
13. Ivan Skoba
14. Adrian Storisteanu
15. Arno T¨ngler
u
16. Kjell Widlert
(USA)
(ITA)
(HUN)
(DEU)
(ISR)
(SVK)
(HRV)
(CZE)
(SVK)
(FRA)
(SVK)
(CAN)
(ROU)
(CZE)
(CAN)
(DEU)
(SWE)
pser-h# 11
0
¥
(2+4) ser-h= 12
¥
1
5£
C+ (4+4) ser-hs# 112
Checkless Chess
= Triton
= Nereide
50
  0
 
0 0
  ¥
!¢ i
!¡
(11+11) ser-h# 19
C+ (6+1)
Antipodean Circe
No wK
Promotions to pawn allowed
 
 
5 
T259 (Alberto Armeni):
1.g5 2.g4+ Ke3 3.g3 4.g2 5.g1=B+ Kd3 6.0-0-0+ Kc4 7.b5+ c×b6 e.p. 8.Rd4+ Kc5 9.Rd8+ Kc6 10.Bh2 11.Bb8 b7 #
Excelsior, Valladao, Miniature, White minimal (Author).
T260 (Gy¨rgy Bakcsi):
o
1.Sd3 6.K×f6 11.Ka1 12.Sb2 Bg7 =
T261 (Paul R˘ican):
a
1.Ke8 6.Kh4 (now, the main plan 7.h5? & 1.Sf2 TRg2-g3# doesn’t work because white has Kf3-e4! So, wPd5 must be captured)
7.Kh3 8.TRh4 9.TRh6 11.Kh5 12.TRh4 13.TRh4-g4 21.K×c1 29.Kh5 30.TRg4-h4 31.TRh4-h2 33.Kh3 34.TRh4 35.TRh4-g4
47.K×a3 59.Kh3 60.TRh4 61.TRh6 63.Kh5 64.TRh4 65.TRg4 66.Kh4 . . . 75.K×a1 . . . 103.K×b3 105.K×d5 106.K×e5 111.Kh4
112.h7-h5 & 1.Sf2 TRg2-g3 #
TRg4-g3+? or TRh2-h3+? or TRg2-g1+? are forbidden (Checkless Chess condition). Zeller cage, rst time with tritons. (Author)
T262 (S´bastien Luce):
e
1.Kf5 2.K×g6(c2) 3.K×f7(b3) 4.K×g8(c4) 5.Kf7 6.Ke6 7.Ke5 8.Kd4 9.Kc3 10.K×c2(g6) 11.K×b3(f7) 12.Kc3 13.Kd4 14.Ke5
15.K×f6(b2) 16.K×g7(c3) 17.K×f8(b4) 18.Kg7 19.Kh8 f8=Q#
The black king has a long way to clear the path for promotion! (Author)
ChessProblems.ca
Bulletin
IIssue
7I
December 2015
http://Bulletin.ChessProblems.ca
189
ORIGINALS
T263
Ivan Skoba
T263:
Consequent:
This is usual play with the
only distinction that all intermediary positions
are evaluated independently of the earlier
moves (similarly to consequent series-
helpmate, where the legality of the position
is reconsidered after each move). In series-
mover this fairy condition is known as Chess,
Consistent. Problem legality of the position
is determined after every move. Invented by
Michel Caillaud in 1979 [ENCYCLOPEDIA
OF CHESS PROBLEMS, 2012]
The author explains:
Consequent Type 3:
in this type the white
king can walk onto squares c4, b4, a4 and
there is no need to prove the last black
move was indeed b7-b5 or c7-c5 (temporarily
paralyzing the bP by Madrasi reason of e.p.
capture); we just assume that black’s last
move was b7-b5 or c7-c5.
T264-B
George P. Sphicas
Ideal-Mate Review
1994
ser-!= 15
Madrasi
2 Solutions
 
0 
1 
¥
2
T264
S´bastien Luce
e
(7+7) ser-= 24
Consequent
 #
5
3
T265
S´bastien Luce
e
C+ (2+5) ser-h= 35*
C+ (14+1) ser-= 28
Promotions to pawn allowed Equipollents Circe
¢ ! 
5
¥ 
  
¡
£
T266
S´bastien Luce
e
¥
0
(1+9)
T263 (Ivan Skoba):
I) 1.Kh4 4.K×e4 8.Ka4 11.d8=B 13.Bh6 14.g5 15.g4 !=
II) 1.g5 4.K×e4 7.Kb4 10.a8=B 11.Bb7! 14.Bh5 15.g4 !=
This composition employs a new type of the
Consequent
condition – in the rst solution after 6.Kc4 the King isn’t checked by
bPb5 because there exists the last black non-checking move b7-b5 (based on the special type of Consequent used here). Similarly
after 7.Kb4 or after 8.Ka4. But in the nal position white cannot play Ka4-b4, as that would now be self-check! Therefore this is
auto-stalemate (ser-!=). Same goes for the second solution. (Author)
T264 (S´bastien Luce):
e
7.K×a1 11.K×e4 14.K×h1 21.K×a8 24.Kd6 =
Simple but it is the most economical orthodox realization of the King four-corners theme. (Author)
T265 (S´bastien Luce):
e
Set play: 1. . . Rg7-f7 =
Solution: 1.Kh8×g7 7.Kg2×h1 8.Kh1×h2 11.Kf3×e4 15.Kb1×a1 19.Kd4×e5 23.Kb8×a8 27.Kd6×d5 28.Kd5×e6 30.Kd7×e8
35.Kg7-h8 e7-e8=S =
Four-corners, this time in ser-h= with set play. The pawn e8 seems ’strange’, but it is the point of the problem! It needs to be
captured! (Author)
T266 (S´bastien Luce):
e
1.K×b2(Bb1) 6.K×d5(c4) 7.K×c4(b3) 9.K×b3(b2) 11.K×b2(Rc1) 15.K×f5(g5) 16.K×g5(h5) 17.K×h5 18.K×g4(f3) 20.K×e4(d4)
22.K×d4(c3) 23.K×c3(b2) 24.K×b2(Ra1) 27.K×d3(d2) 29.Kf2 =
http://Bulletin.ChessProblems.ca
190
ser-= 36
2
0
 
3 ¥
C+ (2+9)
ChessProblems.ca
Bulletin
IIssue
7I
December 2015
ORIGINALS
T267
Branko Koludrovi´
c
Paul R˘ican
a
T267:
C+ WinChloe
ser-sF 112
Circe
0 5
4 0
2 0
 1
#
1
T268
Branko Koludrovi´
c
Paul R˘ican
a
C+ (3+14) ser-!F 126
Circe
0
300
  0
00
2
1¥
T269
S´bastien Luce
e
C+ (2+16) ser-# 17
C+ (1+3) ser-# 23
C+ (1+4)
Equipollents Circe
Equipollents Circe
a7 = Royal Pawn
h7 = Royal Pawn
0
T270
S´bastien Luce
e
 
2
0
T267 (Branko Koludrovi´, Paul R˘ican):
c
a
1.Kh1 2.g4 13.K×c6(c7) 23.K×h2(Sb8) 36.K×c4(Ra8) 53.K×c1 71.K×b3 90.K×b1(Bc8) 109.K×d3(d7) 111.Ke1 112.g5+ K∼ F
T268 (Branko Koludrovi´, Paul R˘ican):
c
a
5.Ka5×b6[+bRh8] 15.Kf1×g1[+bBf8] 29.Kd8 30.c4×d5 48.Kg5×g6[+bBc8] 65.Kb8×c8 81.Kg4×f5[+bSg8] 100.Ke8×f8
121.Ke6×d6[+bPd7] 122.Kd6×e5[+bPe7] 124.d6×e7 126.Kd6×d7 !F
T269 (S´bastien Luce):
e
1.a8=rR 2.rRd8 3.rR×d7(d6) 4.rR×d6(d5) 5.rRe6 6.rR×f6(g6) 7.rRa6 8.rRa5 9.rR×d5(g5) 10.rRd8 11.rRg8 12.rR×g6(g4) 13.rRg8
14.rR×g5(g2) 15.rRg7 16.rR×g4(Rg1) 17.rRh4 #
T270 (S´bastien Luce):
e
1.h8=rS 2.rSg6 3.rSf8 4.rSh7 5.rS×g5(Bf3) 6.rSe6 7.rS×f4(g2) 8.rSe6 9.rSd4 10.rS×f3(Bh2) 11.rSg5 12.rSf7 13.rSh6 14.rS×f5(d4)
15.rSe7 16.rSc6 17.rS×d4(e2) 18.rSb5 19.rSc3 20.rS×e2(Rg1) 21.rSc3 22.rSe4 23.rSf2 #
ChessProblems.ca
Bulletin
IIssue
7I
December 2015
http://Bulletin.ChessProblems.ca
191
ORIGINALS
HC109, Cornel Pacurar (CPB6)
Solutions:
I) 1.Bh1-g2 Ka1-b1 2.Rg1-h1 Kb1-a1 3.Kf1-
g1 Ka1-b1 4.Bg2-f1 Kb1-a1 5.Kg1-g2 Ka1-b1
6.Rh1-g1 Kb1-a1 7.Sf2-h1 Ka1-b1 8.Re2-f2
Kb1-a1 9.Bf1-e2 Ka1-b1 10.Rg1-f1 Kb1-a1
11.Kg2-g1 Ka1-b1 12.Rf2-g2 Kb1-a1 13.Rf1-
f2 Ka1-b1 14.Be2-f1 Kb1-a1 15.Rf2-e2
Ka1-b1 16.Rg2-f2 Kb1-a1 17.Bf1-g2 Ka1-b1
18.Rf2-f1 Kb1-a1 19.Sh1-f2 Ka1-b1 20.Bg2-
h1 Kb1-a1 21.Kg1-g2 Ka1-b1 22.Rf1-g1
Kb1-a1 23.Kg2-f1
II) 1.Kf1-g2 Ka1-b1 2.Rg1-f1 Kb1-a1 3.Kg2-
g1 Ka1-b1 4.Bh1-g2 Kb1-a1 5.Sf2-h1 Ka1-b1
6.Rf1-f2 Kb1-a1 7.Bg2-f1 Ka1-b1 8.Rf2-g2
Kb1-a1 9.Re2-f2 Ka1-b1 10.Bf1-e2 Kb1-a1
11.Rf2-f1 Ka1-b1 12.Rg2-f2 Kb1-a1 13.Kg1-
g2 Ka1-b1 14.Rf1-g1 Kb1-a1 15.Be2-f1
Ka1-b1 16.Rf2-e2 Kb1-a1 17.Sh1-f2 Ka1-b1
18.Rg1-h1 Kb1-a1 19.Kg2-g1 Ka1-b1 20.Bf1-
g2 Kb1-a1 21.Kg1-f1 Ka1-b1 22.Rh1-g1
Kb1-a1 23.Bg2-h1
Hors Concours
HC116
V´clav Kotˇˇovec
a
es
HC117
V´clav Kotˇˇovec
a
es
HC118
Gy¨rgy Bakcsi
o
HC119
Gy¨rgy Bakcsi
o
ser-# 30
C+ (6+1)
White Maximummer
No wK
= Rookhopper
o
o
ser-# 38
C+ (5+1)
White Maximummer
No wK
= Grasshopper
p
h=8
5 5
4
¥
00 0
¥
C+ (2+9)
h#6
BlackChecks
C+ (2+4)
p
HC116 (V´clav Kotˇˇovec):
a
es
HC118 (Gy¨rgy Bakcsi):
o
1.RHg6 2.RHb3 3.RHg3 4.RHa3 5.RHh3 6.RHg2 7.RHg7 8.RHg1 1.e3 K×d3 2.Kg7 K×e3 3.Kf6 K×f3 4.Ke5 K×g2 5.Kd4 K×f2
9.RHg8 10.RHg6 11.RHg5 12.RHg4 13.RHc4 14.RHg6 15.RHg4 6.Kc3 K×e2 7.Kb2 K×d2 8.Ka1 K×c2=
16.RHh4 17.RHb4 18.RHh5 19.RHh6 20.RHf5 21.RHe5 22.RHd5
23.RHc5 24.RHc6 25.RHb6 26.RHb7 27.RHdb5 28.RHc7
29.RHa6 30.RHa7 #
HC117 (V´clav Kotˇˇovec):
a
es
HC119 (Gy¨rgy Bakcsi):
o
1.Gh3 2.Gh4 3.Gh7 4.Gh2 5.Gh8 6.Gh1 7.Ga1 8.Gh1 9.Gf4 10.Ge5 1.c2+ K×c2 2.Qb2+ Kd3 3.Qc3+ Ke4 4.Qd4+ Kf5 5.Qe5+ Kg6
11.Gf6 12.Ga1 13.Gf3 14.Gf6 15.Gf7 16.Gf2 17.Gf8 18.Gf1 19.Gg1 6.Qg7+ B×g7#
20.Ge3 21.Ge6 22.Gf3 23.Gf4 24.Gd6 25.Gf2 26.Gf4 27.Gg3
28.Gh4 29.Ge4 30.Ge3 31.Ge5 32.Gg5 33.Gd5 34.Gd6 35.Gc7
36.Gc6 37.Gg2 38.Gb7 #
HC116, HC117:
C+ WinChloe
ChessProblems.ca
Bulletin
IIssue
7I
December 2015
http://Bulletin.ChessProblems.ca
192

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